7y^2+y=49

Solution for 7y^2+y=49 equation:

7y^2+y=49

We move all terms to the left:

7y^2+y-(49)=0

a = 7; b = 1; c = -49;
Δ = b2-4ac
Δ = 12-4·7·(-49)
Δ = 1373
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$y_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$y_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$y_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(1)-\sqrt{1373}}{2*7}=\frac{-1-\sqrt{1373}}{14}
$
$y_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(1)+\sqrt{1373}}{2*7}=\frac{-1+\sqrt{1373}}{14}
$